Math, asked by dikshitasaikia23, 8 months ago

(1+ tan2A) cotA/ Cosec2A
=
tan A​

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Answered by Anonymous
3

Answer:

(1++tan 2A)cot A /Cosec 2A=tan A

= sec^2A.cot^2A/cosec^2A=tanA

= 1/cos^2A.cosA/sinA /1/sin^2A

= sin^2A/sinA.cosA

= sinA/cosA

= tanA

Answered by Anonymous
2

Answer:

( (1+tan^2 A) cot A ) /cosec^2 A

= ( sec^2 A × cot A ) /cosec^2 A

= ( sec^2 A / cosec^2 A ) × cot A

= tan^2 A × cot A

= tan A

Step-by-step explanation:

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