Question

[1+tan²x/1+cot²x]- [1-tan x/1-cot x]² =0

pls answer fast​​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

ANSWER

f(x)=(1+tanx+tan

2

x)(1−cotx+cot

2

x)

=1−cotx+cot

2

x+tanx−1+cotx+tan

2

x−tanx+1

f(x)=1+cot

2

x+tan

2

x

take two +ve numbers cot

2

x,tan

2

x

∴ By A.M - G.M. inequality

2

cot

2

x+tan

2

x

≥(tan

2

xcot

2

x)

2

1

cot

2

x+tan

2

x≥2

f(x)=1+cot

2

x+tan

2

x≥3

This is True for xϵR except x=

2

4π

,xϵz because at x=

2

4π

,tanx is not define.