Math, asked by rijaljiwan103, 15 days ago

(1/Tan3A+TanA) + (1/Cot3A+CotA) = 1/2Cosec2A

Answers

Answered by llEmberMoonblissll

25

Answer:

Given,

tan3A−tanA

1

−

cot3A−cotA

1

=

kcot2A

LHS

=

cos3A

sin3A

−

cosA

sinA

1

−

sin3A

cos3A

−

sinA

cosA

1

=

sin2A

cos3AcosA

+

sin2A

sin3AsinA

k=

1

= cot2A

Attachments:

Answered by SadPrincess

4

Answer:

hope will help you

good morning

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