Math, asked by diksha4259, 1 year ago

1/tan3A-tanA-1/cot3A-cotA=cot2A​

Answers

Answered by sandy1816
16

Step-by-step explanation:

1/(sin3A/cos3A)-(sinA/cosA)-1/(cos3A/sinA)-(cosA/sinA)

=cosAcos3A/sin3AcosA-cos3AsinA -sinAsin3A/sinAcos3A-cosAsin3A

=cosAcos3A/sin(3A-A)-sinAsin3A/sin(A-3A)

=cosAcos3A/sin2A+sinAsin3A/sin2A

=cosAcos3A+sinAsin3A/sin2A

=cos(A-3A)/sin2A

=cos2A/sin2A

=cot2A

hii D

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