Question

(1+tan6 1/2) (1+tan38 1/2)​

Answer 1

Answer:

2π−6

2π+6

6−2π

3π−6

Solution :

We know that tan−1(tanθ)=θif−π2≤θ≤π2

Hereθ=−6 radians which does not lie between

However 2π−6 lies between −π2andπ2 such that

tan(2π−6)=−tan6=tan(−6)

∴tan−1{tan−6}=tan−1{tan(tan(2π−6))}=2π−6