Question

1)tan9°tan27°tan63°tan81°=?

2)sec50°sin40° +cos40°cosec50°=?

3)cosec21°×cosec69°=1 ( True/ False)​

Answer 1

Answer:

hii I think that it helps you

Step-by-step explanation:

Given

tan81+tan9−(tan63+tan27)

=cot9+tan9−(cot27+tan27)

=

sin9.cos9

(cos9)

2

+(sin9)

2

−

sin27.cos27

(cos27)

2

+(sin27)

2

=

sin9.cos9

1

−

sin27.cos27

1

=

sin18

2

−

sin54

2

=2.

sin54.sin18

sin54−sin18

=

cos36.sin18

4cos36sin18

=4