Question

1/tanA+1/cotA=1/cosA.sinA​

Answer 1

Answer:

1/tanA+1/cotA=1/cosA.sinA

Step-by-step explanation:

Let us solve the LHS,

As we know that, tanA =sinA/cosA

and cotA=cosA/sinA

So, 1/sinA/cosA+1/cosA/sinA

=cosA/sin+sinA/cosA(On multiplying denominators of sinA and cosA with 1, we get it)

Now=(cos^2A+sin^2A)/cosA.sinA(Ontaking Lcm, and by multiplying both numerators, we get it)

1/cosA.sinA(As we know that, cos^2A+sin^2A=1)

Hence, LHS=RHS.

I hope you get my answer,

Thank you.