Question

1+tanA/1-cotA =1+tanA+cotA = 1+secA+cosecA​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

1+tanA/1-cotA =1+tanA+cotA = 1+secA+cosecA​

(1+tanA)/(1-cotA) = 1+tanA+cotA = 1+secA+cosecA​

$\frac{(1+tanA)}{(1-cotA)}*\frac{(1+cotA)}{(1+cotA)} = 1+tanA+cotA = 1+secA+cosecA$

$\frac{(1+tanA+cotA+tanA*cotA)}{1-cot^{2} A}$ = 1+tanA+cotA = 1+secA+cosecA​

$\frac{1+tanA+cotA +1}{1+1-cosec^{2} A} = 1+tanA+cotA = 1+secA+cosecA$

$\frac{2+tanA+cotA}{2-cosec^{2} A} = 1+tanA+cotA = 1+secA+cosecA$