Question

1+tanA/1-tan=cotA+1/cotA-1​

Answer 1

Answer:

Put the value of tan as cotA and add and then rearrange

Explanation:

In LHS,

=1 + tanA / 1 - tan

=1 + 1/cotA / 1 - 1/cotA

= cotA + 1/ cotA / cotA -1 / cotA  (Taking cotA as LCM)

= cotA A + 1 / cotA - 1   (by crossing CosA)

LHS=RHS