Question

1-tanA/1+tanA=cotA-1/cotA+1 is proving

Answer 1

Step-by-step explanation:

$\frac{1 - tanx}{1 + tanx} \\ \\ div \: with \: tanx \\ \\ \frac{ \frac{1 - tanx}{tanx} }{ \frac{1 + tanx}{tanx} } \\ \\ = \frac{ \frac{1}{tanx} - 1}{ \frac{1}{tanx} + 1 } \\ \\ = \frac{cotx - 1}{cotx + 1}$

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