(1+tanA)(1+tanB)=2then what is(A+B)
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Given (1+tanA)(1+tanB)=2
or 1+tan A+tan B+tan A tan B=2
or tan A+tan B+tan A tan B=1
or tan A+tan B=1-tan A tan B
or (tan A+tan B)/1-tan A tan B=1
or tan(A+B)=1 therefore (A+B) is 45
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