Question

(1-tanA)²+(1-cotA)²=(secA-cosecA)²​

Answer 1

Answer:

my maths is really very bad

Step-by-step explanation:

thats why i cant answer

Answer 2

Answer:

${(1 - tanx)}^{2} + {(1 - \frac{1}{tanx}) }^{2} \\ {(1 - tanx)}^{2} + {( \frac{tanx - 1}{tanx} )}^{2} \\ {(1 - tanx)}^{2}(1 + \frac{1}{ {tan}^{2} x} ) \\ {(1 - tanx)}^{2} \frac{(1 + {tan}^{2} x)}{ {tan}^{2}x } \\ {(1 - tanx)}^{2} \frac{ {sec}^{2}x }{ {tan}^{2} x} \\ {(1 - tanx)}^{2} {cosec}^{2} x \\ {(cosecx \: - secx)}^{2} \\ = {(secx \: - cosecx)}^{2}$