Math, asked by dahalalish1602, 3 months ago

(1-tanA)^2+(1-cotA)^2=(secA-cosecA)^2​

Answers

Answered by dsah9628
1

Step-by-step explanation:

Here,

LHS = (1-tanA)²+(1-cotA)²

= (1-2tanA+tan²A)+(1-2cotA+cot²A)

= sec²A-2tanA+cosec²A-2cotA

= sec²A+cosec²A-2(tanA+cotA)

= sec²A+cosec²A-(sinA/cosA + cosA/sinA)

= sec²A+cosec²A-2((sin²A+cos²A)/cosAsinA)

= sec²A+cosec²A-2(1/cosAsinA)

= sec²A+cosec²A-2secAcosecA

= (secA-cosecA) ²

= RHS

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