Math, asked by singhvimla1409, 11 months ago

(1-tanA)2+(1+tanA)2=2sec2A

Answers

Answered by revathijaya18
6

Answer:

2sec2A=2sec2A

Step-by-step explanation:

L.H.S

(1-tanA)2+(1+tanA)2

1+tanA2-2tanA+(1+tanA2+2tanA)

1+tanA2-2tanA+1+tan2A+2tanA

2+2tan2A

2(1+tan2A)

(1+tan2A)=sec2A

2(sec2A)

2sec2A

L.H.S=R.H.S

Answered by dhanalakshmis2524
4

Answer:

Step-by-step explanation:

(1 - tanA)² + (1 +tan A)²  =  1 -2tanA + tan²A  + 1 + 2 tanA + tan²A

                                      = 2 + 2tan²A

                                     = 2( 1+ tan²A)

                                    = 2 sec²A

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