Math, asked by sk3237914, 1 year ago

1 /tanA+cotA=cosA SinA​

Answers

Answered by tanishksethiya
0

Answer :

L.H.S. = 1/( tanA + cot A )

= 1/(sin A/cos A + cosA/sinA)

= 1/{(sin^2 A + cos^2 A)/(sin A.cos A)}

= 1/(1/sin A.cos A )

= sin A . cos A = R.H.S.

Hope it helps

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