1 /tanA+cotA=cosA SinA
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Answer :
L.H.S. = 1/( tanA + cot A )
= 1/(sin A/cos A + cosA/sinA)
= 1/{(sin^2 A + cos^2 A)/(sin A.cos A)}
= 1/(1/sin A.cos A )
= sin A . cos A = R.H.S.
Hope it helps
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