Question

1/(tanA+cotA)=cosA.sinA​

Answer 1

LHS

$= \frac{1}{ \tan(a) + \cot(a) }$

$= \frac{1}{ \frac{ \sin(a) }{ \cos(a) } + \frac{ \cos(a) }{ \sin(a) } }$

$= \frac{ \cos(a) \sin(a) }{ { \sin}^{2} a + { \cos }^{2}a }$

$= \cos(a) \sin(a)$

=RHS

HENCE PROVED

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