1/(tanA + cotA) =cosA sinA
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Answered by
36
tanA=sinA/cosA
cotA=cosA/sinA
use above formulas in LHS.
LHS=
1/(sinA/cosA+cosA/sinA)
=1/(sin^2A+cos^2A)/cosAsinA
sin^2A+cos^2A=1
LHS=1/1/cosAsinA=cosAsinA=RHS.
:-):-):-):-)
PLEASE follow.
cotA=cosA/sinA
use above formulas in LHS.
LHS=
1/(sinA/cosA+cosA/sinA)
=1/(sin^2A+cos^2A)/cosAsinA
sin^2A+cos^2A=1
LHS=1/1/cosAsinA=cosAsinA=RHS.
:-):-):-):-)
PLEASE follow.
Answered by
27
here is your answer mate ✌️
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