Question

(1+tanA + Sec A) (1+cot A - cosec A)
pls answer fast ​

Answer 1

Answer:

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Step-by-step explanation:

now here (1+tanA + Sec A) (1+cot A - cosec A)

=(1+sin A/cos A+1/cos A)(1+cos A/sin A-1/sin A)

=(1+sin A+1/cos A)(1+cos A-1/sin A)

=(cos A+sin A+1/cos A)(cos A+sin A-1/sin A)

=(cos A+sin A+1)(cos A+sin A-1)/sin A.cos A

so here (cos A+sin A+1)(cos A+sin A-1) is in form

(a+b+c)(a+b-c)

=a square+b square-b square+2ab

ie accordingly

sin square A+cos square A-1+2sin A.cos A/sin A.cos A

=1-1+2sin A.cos A/sin A.cos A

=2sin A.cos A/sin A.cos A

=2

Answer 2

Answer:

(secA-cosec) (1+tanA+cotA)=tan A sec A-cotA cosec A