Question

(1+tanA+secA) (1+Cot A _ cosecA)

Answer 1

Answer:

2) don't ask me question from NCERT

Step-by-step explanation:

(sinA+CosA+1)cosA (sin+cos-1)/sinA

(sinA+cosA)^2-1/sinAcosA

sin^2A+cos^2A+2sinAcosA-1/sinAcosA

1-1+2sinAcosA/sinAcosA

2sinAcosA/sinAcosA

=2

Answer 2

$\huge \boxed { \star {\pink { \smile{ \red{ \star{ \mathbf{answer}}}}}}}$

$<font color = voilet>$

$(1 + \tan A + \sec A )(1 + \cot A - \cosec A)$

$\boxed {\pink{ \purple{ \mathbf{ tan \:a = \frac{ \sin(a) }{ \cos(a) } }}}}$

$\boxed {\pink{ \purple{ \mathbf{ cot \:a = \frac{ \cos(a) }{ \sin(a) } }}}}$

$(1 + \frac{ \sin \:a}{ \cos \: a } + \frac{1}{ \cos \: a } )(1 + \frac{ \cos\: a }{sin \: a} - \frac{1}{sin \: a} )$

$(\frac{(cos \: a + sin \: a) +1}{cos \: a} )( \frac{(sin \: a + cos \: a) - 1 }{sin \: a} )$

$( \frac{ {(cos \: a + sin \: a) }^{2} - 1 }{cos \: a \times sin \: a})$

$\frac{ {cos \: a}^{2} + {sin \: a}^{2} + 2sin \: a \: .cos \: a - 1}{cos \: a \: .sin \: a}$

$\frac{2sin \: a.cos \: a}{cos \: a. \: sin \: a}$

$\frac{2(sin \: a \: .cos \: a)}{(sin \: a \: .cos \: a)}$

$\huge \boxed { \star {\pink { \smile{ \red{ \star{ \mathbf{answer = 2}}}}}}}$

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