(1+tanA+secA)(1+cotA-cosecA)=?
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Step-by-step explanation:
=(1+tanA+secA) (1+cotA-cosecA)
=(1+sinA/cosA+1/cosA) (1+cosA/sinA-1/sinA)
=(cosA+sinA+1)(sinA+cosA-1) /sinA•cosA
=(cosA•sinA+sin^2A+sinA+cos^2A+sinA•cosA+cosA-cosA-sinA-1) /sinA•cosA
=(2cosA•sinA) sinA•cosA
=2
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