Math, asked by uk085171, 5 months ago

(1+tanA+secA)(1+CotA-CosecA)

Answers

Answered by dandi19
1
Solution:

Solution:
(1+tanA+secA) (1+cotA-cscA)


= (1+(sinA/cosA)+(1/cosA) (1+(cosA/sinA)-(1/sinA)

= [(cosA+sinA+1)/cosA] [(sinA+cosA-1)/sinA]

= [(cosA+sinA+1) (sinA+cosA-1)]/cosAsinA

= (2cosAsinA+cosA^2A+sin^2A-1)/cosAsinA

= 2cosAsinA/cosAsinA

= 2

Hope this will be helpful.
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