(1+tana+seca) (1+cota-coseca)
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=(1+sinA/cosA+1/cosA)(1+cosA/sinA-1/sinA)
=(1+(1+sinA)/cosA)(1+(cosA-1)/sinA)
=(cosA+sinA+1)/cosA (sinA+cosA-1)/sinA
this is in the formatr of (a+b) x (a-b) which is equal to a^2-b^2
= ((cosA+sinA)^2 - 1^2 )/cosAsinA
= (cos^2A+sin^2A+2sinAcosA - 1)/cosAsinA
=(1+2sinAcosA -1)/cosAsinA
= 2sinAcosA/cosAsinA
=2
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