Question

(1+tanA-secA)*(1+tanA+secA)=2tanA​

Answer 1

Step-by-step explanation:

may be wrong just check it

Answer 2

$(1 + tana - seca)(1 + tana + seca) \\ \\ = ( \frac{cosa + sina - 1}{cosa} )( \frac{cosa + sina + 1}{cosa} ) \\ \\ = \frac{( {cosa + sina)}^{2} - 1 }{ {cos}^{2} a} \\ \\ = \frac{2sinacosa}{ {cos}^{2} a} \\ \\ = 2tana$