1+tanA/sinA + 1+cotA/cosA=1(secA+cosecA)
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Step-by-step explanation:
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Answer:
The R.H.S will be 2(secA+cosecA) and not 1(secA+cosecA)
Step-by-step explanation:
1+tanA/sinA + 1+cotA/cosA = 2(secA+cosecA)
L.H.S:
(1 + tanA) /sinA + (1+cotA)/cosA
= (1+sinA/cosA)/sinA + (1 + cosA/sinA)/cosA
= (cosA+sinA)/cosA*sinA + (sinA+cosA)/sinA*cosA
= (cosA+sinA+sinA+cosA) / cosA*sinA
= 2(cosA+sinA)/cosA*sinA
= 2(cosA/cosA*sinA + sinA/cosA*sinA)
= 2(1/sinA + 1/cosA)
= 2(cosecA + secA).
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