Math, asked by sandip191, 1 year ago

1+tanA/sinA + 1+cotA/cosA = 2(secA+cosecA)

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Answered by tallented
31
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1/sinA +tanA/sinA + 1/cosA + cotA/ cosA
= 2(secA + cosecA)

{ 1/sinA = cosecA ; tanA/sinA = sinA/cosA*sinA =secA ; 1/cosA = secA ; cotA/cosA = cosA/sinA*cosA = cosecA }
Answered by Monika2002
44
hope it helps you
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