Question

1-tanb/1+tanb=cotb-1/cotb+1​

Answer 1

Answer:

$\frac{1-tanB}{1+tanB}=\frac{cotB-1}{cotB+1}$

Step-by-step explanation:

$LHS = \frac{1-tanB}{1+tanB}$

$=\frac{1-\frac{1}{cotB}}{1+\frac{1}{cotB}}\\=\frac{\frac{cotB-1}{cotB}}{\frac{cotB+1}{cotB}}$

$=\frac{cotB-1}{cotB+1}\\=RHS$

Therefore,

$\frac{1-tanB}{1+tanB}=\frac{cotB-1}{cotB+1}$

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