Question

(1+tanº A)cot A
cos ec-A​

Answer 1

Answer:

hence we can prove it but your question is wrong it should be squared on both the sides.

Explanation:

Firstly square on both the sides ,

(sinA+cosecA)^{2} +(cosA+secA)^{2} = 7+tan^{2} +cot^{2}

here starts,

LHS:

=sin^{2}A + cosec^{2} A + 2 sinA cosecA + cos^{2} + sec^{2} + 2 cosA secA.

= 1+2+2+1+cot^{2} +1+tan^{2}

=7+tan^{2} + cot^{2}[/tex].

LHS=RHS

Answer 2

Answer:

Step-by-step explanation:

(1+tanA)cotA -cosecA

=cotA + 1 - cosecA

=1 - (CosecA-cotA)

=Cosec^2A-cot^2A - (cosecA-cotA)

=(cosecA + cotA)(cosecA - cotA) - (cosecA - cotA)

=(cosecA-cotA)(cosecA -cotA -1)