(1-tanø÷1-cotø)²=tan²ø
{hereø means thita }
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Step-by-step explanation:
(1-tanø÷1-cotø)²={(1-sinø/cosø)÷(1-cosø/sinø)}²
={(cosø-sinø/cosø)÷(sinø-cosø/sinø)}²
= (-tanø)²
= tan²ø
Hence proved
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