Math, asked by eenaduads, 6 months ago

(1+tanQ+secQ) (1+cotQ-cosecQ)​

Answers

Answered by ravi2303kumar
3

Answer:

2

Step-by-step explanation:

(1 + tanQ + secQ)  (1 + cotQ - cosecQ)​

= (1+\frac{sinQ}{cosQ}+\frac{1}{cosQ}) (1+\frac{cosQ}{sinQ}-\frac{1}{sinQ})​

= (1+\frac{sinQ}{cosQ}+\frac{1}{cosQ}) (1+\frac{cosQ}{sinQ}-\frac{1}{sinQ})​

= (1+\frac{sinQ}{cosQ}+\frac{1}{cosQ}) (1+\frac{cosQ}{sinQ}-\frac{1}{sinQ})​

= (1+\frac{sinQ+1}{cosQ}) (1+\frac{cosQ-1}{sinQ})​

= (\frac{cosQ+sinQ+1}{cosQ}) (\frac{sinQ+cosQ-1}{sinQ})​

= \frac{(cosQ+sinQ)^2-1^2)}{sinQcosQ}

= \frac{sin^2Q+cos^2Q+2sinQcosQ-1}{sinQcosQ}

= \frac{1+2sinQcosQ-1}{sinQcosQ}

= \frac{2sinQcosQ}{sinQcosQ}

= 2

Answered by itzlovehunter90
1

Answer:

don't know the answer

idiot

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