Question

[1+tantheta+sectheta] [1+cottheta-cosectheta]

Answer 1

Heya■

[1+tan¢+sec¢][1+cot¢-cosec¢]

=)[1+sin¢/cos¢+1/cos¢][1+cos¢/sin¢-1/sin¢]

=)[cos¢+sin¢+1/cos¢][sin¢+cos¢-1/sin¢]


=)(cos¢+sin¢)^2-(1)^2/cos¢*sin¢

=)Cos^2¢+sin^2¢+2sin¢*cos¢-1/cos¢*sin¢

=)1+2sin¢*cos¢-1/cos¢*sin¢

=)2sin¢*cos¢/cos¢*sin¢

=)2 Answer .

hope it help you.

@rajukumar☺

Answer 2

(1 + cos/sin - 1/sin ) (1+1/cos + sin /cos )

( cos + sin - 1) (cos + sin +1 )
---------------------------------------
cos  * sin 

(cos+sin)² - 1²
-----------------
cos * sin

1+ 2 cos sin - 1
-----------------
cos * sin

2