(1-tanx)(1+tan2x)=1+tanx general solution
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(1−tanx)(1+sin2x)=1+tanx
1+sin2x= 1+tanx/1-tanx
(sinx+cosx)^2 = cosx−sinx.sinx+cosx
sinx+cosx=0 or cos 2x−sin 2x=1
tanx=−1 or cos2x=0
I think you will get the hint from this solution.
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