Math, asked by hareshgarg230719664, 9 months ago

1+tanx÷sinx+1+cotx÷cosx=2(secx +cosecx) ​

Answers

Answered by gnagamokshi
0

Answer:

Step-by-step explanation:

1+tanx/sinx+1+cotx/cosx

secx/sinx+cosecx/cosx

(secx*cosx+sinx*cosecx)/sinx*cosx

(1+1)/1/cosecx*1/cosx

2(secx+cosecx)

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