1. Ten can dig a well in 9 days. In how many days can 15 men dig the same w
Ten workers are paid 1680 for one day. How much money will be paid to 28 W
In school, the monthly fee collection of 350 students is 3,85,000. What will be the collection of fee of 58
students for a month?
4. A bag containing 30 apples weighs 6 kg. How much will 1080 such apples weigh
5. The cost of 15 envelopes is 37.50. How many envelopes can be bought for ₹300? what will be the cost of of 20 envelopes?
The total wages of 30 labourers were 3450 per day. What would be the total wages if 10 more labourers were added to them?
A car takes 7 hours to cover a certain distance at the speed of 48 km/h. If the speed is decreased by 20km/h, how much time will it take to cover the same distance?
A man works 8 hours daily and completes a task in 12 days. If he works 6 hours daily, how many days will the same work be completed?
Gatitam takes 5 hours to paint a wall and Gambhir takes 6 hours to paint the same wall. if they work
together, how long will they take to paint the wall?
Answers
Answer:
1) 10 men dig the well in 9 days.
Let's suppose the total work done by these men is one.
So if 10 men take 9 days then 10 men did 1/9 work each day.
Assuming efficiency for each man equal.
Therefore one man does 1/90 work each day.
So 15 men can do 15/90 work each day.
Let no of days taken by 15 men is x.
So, (15/90 )* x= 1
Therefore x = 6
So 15 men can dig well in 6 days
2) Answer: Rs.4704
Step-by-step explanation:
Amount for 10 workers = rs 1680
Amount for 1 worker = 1680/10 = rs.168
Amount for 28 workers = 168*28 =rs.4704
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3)
Total collection of fee in a Month =Rs.3,85,000
⇒Total number of students =350
⇒ Fee of 1 student =385000
350=Rs.1100
⇒ Fees of 58 students for a month =58×1100
=Rs.63800
4)weigh of 30 apples=6kg
weigh of 1 apples=6÷30
weigh of 1080 apples=1080×6÷30
=216kg
5)⇒ cost of 15 envelops = 37.50
∴ cost of 1 envelope = 37.50 ÷ 15
= 2.5 rupees
case 1
total amount of money = 300
cost of 1 envelope = 2.5
∴ number of envelopes that can be bought
= total amount of money ÷ cost of 1 envelope
=300 ÷ 2.5
= 120
case 2
cost of 1 envelope = 2.5
number of envelopes to be bought = 20
∴ cost of 20 envelopes
= cost of 1 envelope × number of envelopes to be bought
= 2.5 × 20
= 50 rupees
now..
answer 1
the number of envelopes that can be bought wuth 300 rupees = 120
answer 2
the cost of 20 envelopes = 50 rupees
6) No of labourers initially = 30
No of labourers finally = 40
30 members - - - - - - - 3450 Rs
40 members - - - - - - - - - x
x = 4600 Rs.
The total wage would be Rs.4600
7) distance=speed×time
7×48=336km is the distance
speed=28km/hour
time=distance/time
=336/28
=12hour
So,the car will take 12 hours to cover the same distance.
8)Total hours required to complete the task = 8 * 12 = 96 hours
If he works only 6 hours per day then total days in which he will complete the task is
= 96 hours / (6 hours/day)
= 16 days
Task will be done in 16 days.
9)Gautam takes 5 hours to paint the wall.
In 1 hour, Gautam will paint ( 1 / 5 ) of the wall.
Gambhir takes 6 hours to paint the wall.
In 1 hour, Gambhir will paint ( 1 / 6 ) of the wall.
Adding the part of wall Gautam and Gambhir paint in 1 hour,
( 1/5 + 1/6 )
( 6/30 + 5/30 )
( 11 / 30 )
Hence in 1 hour, Gautam and Gambhir will together paint ( 11 / 30 ) of the wall.
Therefore,
Gautam and Gambhir will together take ( 30 / 11 ) hours i.e. ( ) hours to paint the wall.
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