Math, asked by kushal6422, 1 year ago

1
 {1}^{0} \times  {2}^{0} +  {3}^{0} \times  {4}^{0} +  {5}^{0} \times  {6}^{0}
what will be the answer for that one

Answers

Answered by prerna2018
2
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1^0×2^0+3^0×4^0+5^0×6^0
=> 1×1+1×1+1×1
=> 1+1+1
=> 3

HOPE IT HELPS UH!!

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Answered by Anonymous
2

Hii

you are welcome in my ans

1 + 1 + 1 =3

since

a^0 = 1

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hope it may helps you✊✌️

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