Question

1
$1 \div a {}^{2} + 3a + 2 + 1 \div a {}^{2} + 5a + 6 - 2 \div a {}^{2} - 4a + 3$
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Answer 1

COULDN'T ABLE TO GET UR QUESTION

Answer 2

Answer:

take 1/a^2 common(3a+2)+(5a+6)-2/a^2(-4a+3)

=1/a^2(5a-5a+6)-2/a^2(-a)

=1/a^2(6)...so one (a) gets cancel so=a

again A cancels..so answer is = -12/a