Question

1
$\frac{1}{ {8a}^{2} } + \frac{8}{b {}^{2} }$
​

Answer 1

$\huge{\underline\red{\underline\blue{\underline\green{Question:-}}}}$

→ $\frac{1}{ {8a}^{2} } + \frac{8}{b {}^{2} }$

$\huge{\underline\red{\underline\blue{\underline\green{Question:-}}}}$

→ $\frac{1}{ {8a}^{2} } + \frac{8}{b {}^{2} }$

Taking LCM we get :-

→ $\frac{{b}^{2}+{64}{a}^{2}}{8×{a}^{2}×{b}^{2}}$

so the simplified answer is :-

→ $\boxed{\frac{{b}^{2}+{64}{a}^{2}}{8×{a}^{2}×{b}^{2}}}$

Answer 2

Answer:

\huge{\underline\red{\underline\blue{\underline\green{Question:-}}}}

Question:−

→ \frac{1}{ {8a}^{2} } + \frac{8}{b {}^{2} }

8a

2

1

+

b

2

8

\huge{\underline\red{\underline\blue{\underline\green{Question:-}}}}

Question:−

→ \frac{1}{ {8a}^{2} } + \frac{8}{b {}^{2} }

8a

2

1

+

b

2

8

Taking LCM we get :-

→ \frac{{b}^{2}+{64}{a}^{2}}{8×{a}^{2}×{b}^{2}}

8×a

2

×b

2

b

2

+64a

2

so the simplified answer is :-

→ \boxed{\frac{{b}^{2}+{64}{a}^{2}}{8×{a}^{2}×{b}^{2}}}

8×a

2

×b

2

b

2

+64a

2