Question

(1) The 4th, 7th and 10th terms of a GP. are a, b, c
respectively. Show that b2 = ac.​

Answer 1

Step-by-step explanation:

Let 1st term= A &

Common ratio= r

so, 4th term a= Ar^3

7th term b= Ar^6 &

10th term c= Ar^9

now, b^2= (Ar^6)^2= A^2r^12

and ac= (Ar^3)(Ar^9)=A^2r^12

so, b^2=ac proved