Question

1. The 6th term of an A.P. is 16 and the 14" term
is 32. Determine the 36th term.​

Answer 1

Step-by-step explanation:

$6th \: term \: = a + (6 - 1)d \\ 16 = a + 5d \\ 14th \: term \: = a + (14 - 1)d \\ 32 = a + 13d$

On eliminating the eq 1 &2

$d = 2$

On putting in eq 1

$16 = a + 5(2) \\ 16 - 10 = a \\ a = 6$

$36th \: term \: = a + (36 - 1)d \\ = 6 + 35 \times 2 \\ = 6 + 70 \\ = 76$