Question

1. The ∆ABC of angle ABC in the figure is the external angle. If angle B=40°,angleA=70°. then draw m angle A CD.​

Answer 1

Step-by-step explanation:

We are given m∠B=40

o

m∠A=70

o

Now,

BD

is a straight ray

so, m∠ACB+m∠ACD=180

o

→(1)

In △ABC,m∠A+m∠B+m∠ACB=180

o

→(2)

From (1) & (2)

m∠A+m∠B=m∠ACD

so, m∠ACD=40

o

+70

o

m∠ACD=110

o