Question

1.The age of a man is 4 times that of his son.5 years ago , the man was nine times as old as his son was at that time. what is the present age of the man? 2.there is an equilateral triangle of which each side is 2m with all the three corners circle as centres circles are described each of radius 1m .calculate the area common to all the circles. 3.A man bought 13 shirts of birr 50 each ,15 pants of birr 60 each and 12 pairs of shoes at birr 65 a pair. find the average value of each particle.

Answer 1

Answer:

$</p><p></p><p>146</p><p></p><p>Q:</p><p></p><p>The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is? </p><p></p><p>Answer:</p><p></p><p>Let the son's age be x years and the father's age be 4x years </p><p></p><p></p><p></p><p></p><p></p><p>       5x = 40</p><p></p><p></p><p>        x = 8</p><p></p><p></p><p> present age of the father =  =  = 32 years</p><p></p><p>$

Step-by-step explanation:

146Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Answer:

Let the son's age be x years and the father's age be 4x years

5x = 40

x = 8

\inline \therefore present age of the father = \inline 4x = \inline 4\times 8 = 32 years

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