Math, asked by abedabatti1, 5 days ago

1. The ages of Gauri and Geeta are in the ratio of 3:4. Five years from now the ratio of their ages will be 2:3. Find their present ages.​

Answers

Answered by sujaykatoch100
0

Answer:

Gauris age = -10 Geetas age = -15

Step-by-step explanation:

Let the present age of gauri = 3x and geeta = 4x

After 5 years, gauris age = 3x + 5 and geeta = 4x + 5

According to question,

3x + 5 : 4x + 5 = 2:3

3x+5/4x+5 = 2/3

After cross multiplying,

9x + 15 = 8x + 10

x = -5

Answered by ammubuddi
2

Step-by-step explanation:

the ratio of gauri and geeta present age is 3:4

so, let their ages be 3x and 4x

after five years their ages will be in ratio 2:3

therefore,

(3x+3)/(4x+3) = 2/3

or, 3(3x+3) = 2(4x+3)

or, 9x+9 = 8x+6

or, 9-6 = 9x - 8x

or, 3 = 1x

or, x = 3

therefore, present age of gauri = 3x = (3×3) =9 years

present age of geeta = 4x = (4×3) = 12 years

the sum of their age is 9+12 =21 years

Hope it's helpful

All the best

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