Question

1. The amplitude and time period of a simple pendulum bob are 0.05 m and 2 s respectively. Then the maximum velocity of the bob is
a) 0.157 ms -1
b) 0.257 ms
c) 0.10 ms s-1
d) 0.025 ms
and explain your answer​

Answer 1

Answer:

a) 0.157 m/s

Explanation:

Vmax = Aw

W = 2*3.14/T = 2*314/2

W = 3.14

Vmax= 0.05*3.14

         = 0.157 m/s

Answer 2

Answer:

a)0.157 ms-1

Explanation:

V max = 0.05 / pie

= 0.05/ x 22/7

=0.157