Question

1. The area of a parallelogram is ‘y’ cm2 and its height is ‘h’ cm.The base of another parallelogram is ‘x’ cm more than the first parallelogram and its area is twice the area of the first.Find, in terms of ‘y’,’h’ and ‘x’, the expression for the height of the second parallelogram

Answer 1

Answer:

area of 1st parallelogram = y cm square, height = h cm

Area= Base\times Height

y=b×h ----eq 1

Base =b=y/h

area of 2nd parallelogram = 2y cm square, height = H cm

Base of 2nd parallelogram =

h

y

+x

2y=(

h

y

+x)×H

H=

(y+hx)

2yh

Hops it helps⚡