Math, asked by rachanashinde7a62, 1 month ago

1. The area of a rectangle garden of length 40m, is 1000 sqm. Find the

breadth of the garden and its perimeter. The garden is to be enclosed by 3

rounds of fencing, leaving an entrance of 4 m. Find the cost of fencing

The garden at a rate of 250 rupees per meter.​

Answers

Answered by rashmigaonkar1215
1

Step-by-step explanation:

area = l*b

1000 = 40*b

b= 1000/40

b= 25m

perimeter= 2(l+b)

=2(40+25)

= 2(65) = 130m

perimeter for 3 rounds= 130*3= 390m

subtracting 4 in each round, 390-4(3)= 390-12= 378m

cost of fencing for 1m= ₹250

Therefore cost of fencing 378m = 378*250 = ₹94,500

Answered by jaspreetsingh5890
2

Answer:

Breadth of the garden=25m

Perimeter=130m

Step-by-step explanation:

Area=1000

l*b=1000

b=1000/l

b=1000/40

b=25m

Perimeter=2(l+b)=2(40+25)=130

Entrance=4m

Perimeter to be fenced=130-4=126m

Total perimeter to be fenced=3*126=378m

Given cost of fencing is Rs. 250 per m

So, Total cost=250*378= Rs. 94500

Similar questions