1. The area of a rectangle garden of length 40m, is 1000 sqm. Find the
breadth of the garden and its perimeter. The garden is to be enclosed by 3
rounds of fencing, leaving an entrance of 4 m. Find the cost of fencing
The garden at a rate of 250 rupees per meter.
Answers
Answered by
1
Step-by-step explanation:
area = l*b
1000 = 40*b
b= 1000/40
b= 25m
perimeter= 2(l+b)
=2(40+25)
= 2(65) = 130m
perimeter for 3 rounds= 130*3= 390m
subtracting 4 in each round, 390-4(3)= 390-12= 378m
cost of fencing for 1m= ₹250
Therefore cost of fencing 378m = 378*250 = ₹94,500
Answered by
2
Answer:
Breadth of the garden=25m
Perimeter=130m
Step-by-step explanation:
Area=1000
l*b=1000
b=1000/l
b=1000/40
b=25m
Perimeter=2(l+b)=2(40+25)=130
Entrance=4m
Perimeter to be fenced=130-4=126m
Total perimeter to be fenced=3*126=378m
Given cost of fencing is Rs. 250 per m
So, Total cost=250*378= Rs. 94500
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