Question

1. The area of a rectangular field is 250 m². If the breadth of the field is 10 m, find its length.
(a) 25 m
(b) 50 m
(c) 100 m
(d) 125 m​

Answer 1

Answer:

25m

Step-by-step explanation:

area of rectangle=l×b

250=10×L

L=250/10

L=25

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt 1.\:\: The \:area \:of\: a\: rectangular\: field\: is \:250\: {m}^{2}. If\: the\\\tt breadth\: of\: the\: field\: is\: 10\: m, \:find\: its\: length.$

$\tt (a)\:\: 25\: m$

$\tt (b) \:\:50 \:m$

$\tt (c)\:\: 100\: m$

$\tt (d) \:\:125\: m$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf The\:area\:of\:rectangular \:field(A) =250\:{m}^{2}$
• $\sf \bf Breadth \:of \:the\:rectangular \:field(b) =10\:m$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Length \:of \:the\:rectangular \:field(l)$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\pink{\underline {\sf The\:length \:of \:the \:rectangular \:field}}}$

${\blue {\boxed {\boxed {\boxed {\green {\sf \bf A=l \times b}}}}}}$

• $\sf A=area\:of \:rectangular \:field$
• $\sf l=length\:of \:rectangular \:field$
• $\sf b=breadth\:of \:rectangular \:field$

${\underbrace {\overbrace {\orange {\bf Substitute \:the \:values}}}}$

$\sf \bf \implies 250=l \times 10$

$\sf \bf \implies 250=10l$

$\sf \bf \implies l=\dfrac{250}{10}$

$\sf \bf \implies l=\dfrac{25\cancel {0}}{1\cancel {0}}$

$\implies{\blue{\boxed {\boxed {\purple {\mathfrak {l=25\:m}}}}}}$

${\underbrace {\red {\underline {\red {\overline {\red {\sf \therefore The\:length \:of \:the \:rectangular \:field\:is \:25\:m}}}}}}}$

${\underbrace {\red {\underline {\red {\overline {\red {\sf \therefore Option \:(a) \:25\:m\:is\:correct}}}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\bf Area \:of \:rectangle = l\times b$

$\bf Perimeter \:of \:rectangle = 2(l+b)$

$\bf Diagonal \:of \:rectangle = \sqrt{{b}^{2}+{l}^{2}}$