Question

1. The area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm is ____cm²​

Answer 1

Answer:

82cm²

Step-by-step explanation:

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Answer 2

Answer:

The area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm is 41 cm².

Step-by-step explanation:

Given :

• Diagonals are 10 cm and 8.2 cm.

To Find :

• Area of rhombus.

Calculations :

Here, we are provided with the diagonals of lengths 10 cm and 8.2 cm. And we have to calculate the area of rhombus. Area of rhombus is given by,

• $\underline{\underline{\boxed{ \rm{Area_{(Rhombus)} = \dfrac{1}{2} \times d_{1} \times d_{2}}}}}$

Where,

• $\sf{d_{1}}$ (Diagonal 1) $\rightarrow$ 10 cm
• $\sf{d_{2}}$ (Diagonal 2) $\rightarrow$ 8.2 cm

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$\dag$ Putting the values,

$\longrightarrow \rm Area_{(Rhombus)} = \dfrac{1} {\not{2}} \times \cancel10 \: cm \times 8.2 \: cm \\ \\ \\ \longrightarrow \rm Area_{(Rhombus)} = 5 \: cm \times 8.2 \: cm \\ \\ \\ \longrightarrow{ \red{\rm Area_{(Rhombus)} = 41 \: cm^2}}$

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Therefore,

• The area of rhombus is 41 cm².

_______________________

$\dag$ More Formulae :

• Perimeter of rhombus = $\sf Perimeter = 4 \times Area$

• Area of parallelogram = base × height

• Area of triangle = $\sf \dfrac{1}{2}$ × base × height

• Area of equilateral triangle = $\sf \: \dfrac{\sqrt{3}}{4} \: a^2$

• Heron's formulae for calculating the area (triangle) = $\sf \: \sqrt{s(s - a)(s - b)(s - c) \: sq. \: unit}$