1. The area of a square park is same as of a rectangular park. If the side of the square park is 80 m and the length of the rectangular park is 100 m, find the breadth of the rectangular park. Which figure encloses more perimeter
Answers
Answer:
- The breadth of the rectangular park is 64 m.
- Rectangular park encloses more perimeter.
Step-by-step explanation:
Given that:
- The area of a square park is same as of a rectangular park.
- The side of the square park is 80 m.
- The length of the rectangular park is 100 m.
To Find:
- The breadth of the rectangular park.
- Which figure encloses more perimeter?
Let us assume:
- The breadth of the rectangular park be x.
Formula used:
- Area of a square = (Side × Side)
- Area of a rectangle = (Length × Breadth)
- Perimeter of a square = (4 × Side)
- Perimeter of a rectangle = 2(Length + Breadth)
Finding the breadth of the rectangular park:
- According to the question.
Area of square park = Area of rectangular park
- Substituting the values.
⟼ (80 m × 80 m) = (100 m × x)
⟼ 6400 m² = 100 m × x
⟼ x × 100 m = 64 m × 100 m
- 100 m cancelled both sides.
⟼ x = 64 m
∴ The breadth of the rectangular park = 64 m
Finding the perimeter of square park:
- Perimeter of square park = (4 × 80 m)
- Perimeter of square park = 320 m
Finding the perimeter of rectangular park:
- Perimeter of rectangular park = 2(100 m + 64 m)
- Perimeter of rectangular park = 2 × 164 m
- Perimeter of rectangular park = 328 m
What we get:
- After finding the perimeter of square park and rectangular park we get that the perimeter of rectangular park is greater than that of square park.
Answer:
Given :-
Area of square = Area of rectangle
Side of Square = 80 m
Length of park = 100 m
To Find :-
Who encloses more Perimeter
Breadth
Solution :-
Side × side = Length × Breadth
80 × 80 = 100 × Breadth
6400 = 100 × Breadth
6400/100 = Breadth
64 = Breadth
Now
Perimeter of Rectangle = 2l + 2b
=> 2(l + b)
=> 2(100 + 64)
=> 2(164)
=> 328 cm
Now,
Perimeter of square = side × 4
=> 80 × 4
=> 320 cm
Therefore,
Perimeter of Rectangle is greater