Question

1) The atomic numbers of five elements a ,b, c ,d and e are 6,8, 3,7 and 9 respectively

a) Which is the element having the highest electropositivity among these elements why?

b) Which is the element having the least metallic character among these elements why?

c) What is the conclusion about the relationship between metallic character and electropositivity of an element?


Please say the accurate answer

Answer 1

Atomic no. 3 which refers to Li which is a highly electropsitive element in s block

Atomic no. 9 refers to flourine which has least metalic character

Final conclusion is that-:

1.)electropsitivity decreases when we go from left to right in periodic table so order of given atomic no elements

3 6 7 8 9 are in decrasing order of electropositivity

2.) metallic character is also decrease when we go from left to right in periodic table so same order 3 6 7 8 9 comes out