Question

1. The atomic radius of an element which crystallises in body centred cubic lattice is 120 pm. Calculate
the lattice constant.
(Ans. 277.1 pm]
​

Answer 1

Answer:

Explanation:

Calculate the Lattice Constant

If the space lattice is FCC, the lattice constant is given by the formula [4 x r / (2)1/2] and if the space lattice is BCC, then the lattice constant is given by the formula a = [4 x r / (3)1/2]

Answer 2

$\huge \bold \color{lime} \star{\underline{ \color{fuchsia} \mathfrak{Answer }} \star}$

Radius = 120 pm

For body centred cubic(bcc) lattice,

$4r = a \sqrt{3}$

Where 'r' = radius and 'a' = edge length

$a = \frac{4r}{ \sqrt{3} }$

$a = \frac{4 \times 120}{1.73}$

$\huge \bold \color{green} \boxed{a = 277.1 \: pm}$

Hope it helps...