Question

1.The autorickshaw fare in a city is charged as ₹10 for the first kilometre and at ₹4 per
kilometre for subsequent distance covered. Write the linear equation to express the
above statement. Draw the graph of linear equation. pls answer with graph 25 points

Answer 1

Answer:

Let the total distance covered be x km

and, the total fare be Rs. y

Since, Total fare = fare for the first kilometer + fare for the remaining kilometer of distance (1)

We know that the fare for first kilometer is Rs. 10

Fare for the remaining kilometers i.e. (x - 1)

= 4(x - 1)

Put values in (1)

⇒ y = 10(1) + 4(x - 1)

⇒ y = 10 + 4x - 4

⇒ y = 4x + 6

When x = 0, we have, y = 4 × (0) + 6, So, y = 6

When x = - 1, we have, y = 4 × (- 1) + 6, = - 4 + 6

So, y = 2

When x = - 2, we have, y = 4 × (- 2) + 6 = - 8 + 6

So, y = - 2

x = 0 ; y = 6

x = - 1 ; y = 2

x = - 2 ; y = - 2

Answer 2

Let the total distance covered be x km and the fare charged Rs y. Then for the first km, fare charged is Rs 10 and for remaining (x –1) km fare charged is Rs 4 (x – 1). Therefore, y = 10 + 4(x – 1) = 4x + 6 The required equation is y = 4x + 6. Now, when x = 0, y = 6 and when x = –1, y = 2.Read more on Sarthaks.com - https://www.sarthaks.com/868656/autorikshaw-fare-city-charged-for-first-kilometer-kilometer-subsequent-distance-covered.

question is unsame but helpful